In: Statistics and Probability
How much does a sleeping bag cost? Let's say you want a sleeping bag that should keep you warm in temperatures from 20°F to 45°F. A random sample of prices ($) for sleeping bags in this temperature range is given below. Assume that the population of x values has an approximately normal distribution. 65 75 35 65 70 60 30 23 100 110 105 95 105 60 110 120 95 90 60 70 (a) Use a calculator with mean and sample standard deviation keys to find the sample mean price x and sample standard deviation s. (Round your answers to two decimal places.) x = $ s = $ (b) Using the given data as representative of the population of prices of all summer sleeping bags, find a 90% confidence interval for the mean price μ of all summer sleeping bags. (Round your answers to two decimal places.) lower limit $ upper limit $
Values ( X ) | ||
65 | 147.6225 | |
75 | 4.6225 | |
35 | 1776.6225 | |
65 | 147.6225 | |
70 | 51.1225 | |
60 | 294.1225 | |
30 | 2223.1225 | |
23 | 2932.2225 | |
100 | 522.1225 | |
110 | 1079.1225 | |
105 | 775.6225 | |
95 | 318.6225 | |
105 | 775.6225 | |
60 | 294.1225 | |
110 | 1079.1225 | |
120 | 1836.1225 | |
95 | 318.6225 | |
90 | 165.1225 | |
60 | 294.1225 | |
70 | 51.1225 | |
Total | 1543 | 15086.55 |
Mean
Standard deviation
Confidence Interval
Lower Limit =
Lower Limit = 66.2549
Upper Limit =
Upper Limit = 88.0451
90% Confidence interval is ( 66.25 , 88.05 )