Within what pH range can Cu2+ be separated from Fe2+ if their
concentration is both 0.1M and H2S concentration is 0.01M? Show all
calculations to support your answer. (KCuS = 1.2x10^-36; KFeS =
4.9x10^-18; KH2S = 1.3x10^-20)
A voltaic cell consists of a Pb/Pb2+ half cell and a
Cu/Cu2+ half cell at 25C. The initial
concentrations of Pb2+ and Cu2+ are 0.0520 M
and 0.150 M respectively.
Part A: What is the initial cell potential
*Write answer using two significant figures
Part B: What is the cell potential when the concentration of
Cu2+ has fallen to 0.210 M
*Write answer using three significant figures
Part C: What is the concentration of Pb2+ when the
cell potential falls...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+
half-cell at 25 ∘C. The initial concentrations of Pb2+ and Cu2+ are
5.30×10−2 M and 1.60 M , respectively.
Part A
What is the initial cell potential? Express your answer using
two significant figures.
Ecell= ? V
Part B
What is the cell potential when the concentration of Cu2+ has
fallen to 0.230 M ?
Express your answer using two significant figures.
Part B
What is the cell potential...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+
half-cell at 25 ∘C. The initial concentrations of Pb2+ and Cu2+ are
5.00×10−2 M and 1.70 M, respectively. What is the cell potential
when the concentration of Cu2+ has fallen to 0.250 M ? What are the
concentrations of Pb2+ and Cu2+ when the cell potential falls to
0.37 V?
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+
half-cell at 25 ∘C. The initial concentrations of Pb2+ and Cu2+ are
0.0500 M and 1.50 M , respectively.
Standard Reduction Half-Cell Potentials at 25 ∘C Half-Reaction
E∘(V)
Cu+(aq)+e−→Cu(s) 0.52
Cu2+(aq)+2e−→Cu(s) 0.34
Cu2+(aq)+e−→Cu+(aq) 0.16
Pb2+(aq)+2e−→Pb(s) −0.13
1. What is the initial cell potential? Express your answer using
two decimal places.
2. What is the cell potential when the concentration of Cu2+
falls to 0.200 M ? Express your answer...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+
half-cell at 25 ∘C. The initial concentrations of Pb2+ and Cu2+ are
5.00×10−2 M and 1.50 M , respectively
What is the initial cell potential?
0.51V
What is the cell potential when the concentration of Cu2+ has
fallen to 0.200 M ?
0.45V
Part C What are the concentrations of Pb2+ and Cu2+ when the
cell potential falls to 0.360 V ?
I need help with Part C
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+
half-cell at 25 ∘C. The initial concentrations of Pb2+ and Cu2+ are
5.20×10−2M and 1.50 M,
respectively.
A) What is the cell potential when the concentration of Cu2+ has
fallen to 0.250 M ?
B) What are the concentrations of Pb2+ and Cu2+ when the cell
potential falls to 0.36 V?