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A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 ∘C. The...

A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 ∘C. The initial concentrations of Pb2+ and Cu2+ are 0.0500 M and 1.50 M , respectively.

Standard Reduction Half-Cell Potentials at 25 ∘C Half-Reaction E∘(V)

Cu+(aq)+e−→Cu(s) 0.52

Cu2+(aq)+2e−→Cu(s) 0.34

Cu2+(aq)+e−→Cu+(aq) 0.16

Pb2+(aq)+2e−→Pb(s) −0.13

1. What is the initial cell potential? Express your answer using two decimal places.

2. What is the cell potential when the concentration of Cu2+ falls to 0.200 M ? Express your answer using two decimal places.

3. What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.37 V ? Enter your answers numerically separated by a comma. Express your answer using two significant figures.

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queen_honey_blossom answered 2 years ago
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