Question
In: Chemistry
What is the initial pH of a titration of 25.0 mL of 0.126 M NH3 with...
What is the initial pH of a titration of 25.0 mL of 0.126 M NH3 with 0.287 M HCl? Kb = 1.8 x 10-5 SHOW WORK
a. 11.18
b. 7.00
c. 2.82
d. 1.04
e. 0.54
Solutions
Expert Solution
NH3 + H2O --------------> NH4+ + OH-
0.126 M 0 0
0.126-x x x
Kb = [NH4+] [OH-] /[NH3]
1.8 x 10-5 = x.x / 0.126-x
Since x is very small, 0.126 -x = 0.126
Then,
1.8 x 10-5 = x.x / 0.126
x = 0.0015 M
[OH-] = 0.0015 M
pOH = - log [OH-] = - log (0.0015) = 2.82
Hence,
pH = 14 -pOH= 14- 2.82= 11.18
Therefore,
Initial pH = 11.18
--------------------------------------
Ans = a
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