Question
In: Chemistry
A buffer is prepared by mixing 25.0 mL of 0.500 M NH3(aq) with 25.0 mL of...
A buffer is prepared by mixing 25.0 mL of 0.500 M NH3(aq) with 25.0 mL of 0.200 M HCl (aq). What is the pH of the buffer? [ Kb (NH3) = 1.8 x 10-5 ]
Solutions
Expert Solution
HCl + NH3 -----------------> NH4Cl
25 x0.2 25 x0.5 0
5 12.5 0 ------------initial
0 7.5 5 ------------ after reaction
NH3 and NH4Cl mixture remained . it can act as buffer
Kb of NH3 = 1.8 x10^-5
pKb= -logKb= 4.74
pOH = pKb + log [salt/base]
= 4.74 + log[5/7.5]
= 4.56
PH= 14-pOH= 14-4.56
pH = 9.43
queen_honey_blossom answered 14 hours agoRelated Solutions
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