In: Chemistry
mL HCl added |
pH |
0.00 |
11.86 |
25.0 |
10.71 |
50.0 |
6.09 |
A titration of 25.0 mL of 0.100 M triethylamine ((CH3CH2)3N) was performed with 0.0500 M HCl. Given the following data calculate the pKa for triethylammonium ion.
answer :pKa= 10.71
(C2H5)3N + HCl-------------------->(C2H5)3NH+Cl- (salt)
25 x 0.1 0.05 x 25 0
2.5 1.25 0 at equivalence point
1.25 0 1.25
so in the solution salt + base remained. it can form buffer
now basic buffer pH formula
pH = 14