In: Physics

A spring balance has a scale that reads from 0 to 50 kg. The length of the scale is 20 cm. A body suspended from this balance, when displaced and released, oscillates with a period of 0.6 s. What is the weight of the body?

Given

Maximum mass that the scale can read, M = 50 kg

Maximum displacement of the spring = Length of the scale, l = 20 cm

= 0.2 m

Time period, T = 0.6 s

Maximum force exerted on the spring, F = mg

Where,

g = acceleration due to gravity = 9.8 m/s2

F = 50 x 9.8 = 490

Hence,

Spring constant, k = F / l

= 490 / 0.2

We get,

= 2450 N m-1

Mass m is suspended from the balance.

Time period, t = 2π√m / k

Therefore,

m = (T / 2π)2 x k

= {0.6 / (2 x 3.14)}2 x 2450

We get,

= 22.36 kg

Hence, weight of the body = mg = 22.36 x 9.8

On calculation, we get,

= 219.13 N

Therefore, the weight of the body is about 219 N

The weight of the body is about 219 N.

Latest Questions

- How far does the pendulum bob (the ball at the end of the rope) travel in one complete cycle of motion if its length is 32.7 cm?
- Find the time th it takes the projectile to reach its maximum height H. Express th in terms of v0, theta, and g (the magnitude of the acceleration due to gravity).
- Role of HCL and Liver in our body
- Nutrition in Humans
- Nuitrion in Amoeba and Paramoecium
- Briefly explain the female reproductive system
- Briefly explain the male reproductive system