In: Chemistry
To determine the ammonia concentration in a sample of lake water, you mix 10.0 mL of lake water with 5 mL of phenol solution and 2 mL of sodium hypochlorite solution and dilute to 25.0 mL in a volumetric flask (sample A). To a second 10.0 mL solution of lake water you add 5 mL of phenol, 2 mL of sodium hypochlorite, and 2.50 mL of a 5.50 × 10–4 M ammonia solution and dilute to 25.0 mL (sample B). As a reagent blank, you mix 10.0 mL of distilled water with 5 mL of phenol, 2 mL of sodium hypochlorite and dilute to 25.0 mL (sample C). You measure the following absorbances using a 1.00 cm cuvet:
Sample: Absorbance: (625nm)
A 0.479
B 0.726
C 0.045
What is the molar absorptivity (ε) of the indophenol product, and what is the concentration of ammonia in the lake water?
Sample A = 10 mL lake water + 5 mL Phenol+ 2 mL Sodium Hypoclorite Sample
SampleB = 10 mL lake water + 5 mL Phenol+ 2 mL Sodium Hypoclorite + 2.5 mL 5.5 x 10-4 M NH3 Sample + sandard Soltion
Sample C = 10 mL distilled water + 5 mL Phenol+ 2 mL Sodium Hypoclorite Blank
OD
Sample A Sample 0. 479
SampleB Sample + Standard Solution 0. 726
Sample C Blank 0.045
To get the OD of standard solution alone = ODA-ODB = 0.726 - 0.479 = 0.247
Given standard NH3 solution concentration is 5.5 x 10-4 M and we have taken 2.5 mL and diluted to 25 mL.
Therefore, the net concentration of [NH3] from standard solution = 2.5 mL x 5.5x10-4 M/ 25 mL = 5.5 x 10-5 M
From Beers lamberts law;
OD = e.c.l
0.247 = e x 5.5 x 10-5 M x 1 cm
e = 4.5 x 103 M-1 cm-1
Ammonia concentration in the lake water :
ODsample = ODA - ODC = 0.478 - 0.045 = 0.433
Again from Beers law;
ODsample = e.c.l
0.433= 4.5x103 M-1cm-1 x C x 1 cm
[NH3] = C = 9.62x 10-5 M
Therefore, Answer : Molar absorptivity (ε) of the indophenol = 4.5 x 103 M-1cm-1
The concentration of ammonia in the lake water [NH3]lake water = 9.62 x 10-5 M