In: Math
How much money do people spend on graduation gifts? In 2007, a
federation surveyed 2415 consumers who reported that they bought
one or more graduation gifts that year. The sample was selected in
a way designed to produce a sample representative of adult
Americans who purchased graduation gifts in 2007. For this sample,
the mean amount spent per gift was $58.15. Suppose that the sample
standard deviation was $20. Construct a 98% confidence interval for
the mean amount of money spent per graduation gift in 2007. (Round
your answers to three decimal places.)
( , )
Interpret the interval.
We are 98% confident that the mean amount of graduation money spent was within this interval.
We are 98% confident that the mean amount of money spent per graduation gift in 2007 was within this interval.
We are confident that the mean amount of money spent per graduation gift in 2007 was within this interval 98% of the time.
We are confident that 98% of the amount of money spent per graduation gift in 2007 was within this interval.
Let us assume that our sample( x1, x2, ....., xn) is drawn from normal population.
So , xi ~ and mean of all sample values will be and
~
Thus 1- % confidence interval of is given by
Here 58.15
sample standard deviation is 20
When is unknown and , we take sample standard deviation as the estimator of
That is
n=2415
is our confidence interval
Using this values we have ,
Lower confidence limit = = 58.131
Upper confidence limit = = 58.169
Hence confidence interval is (58.131, 58.169)
This would be the interpretation:
We are confident that the mean amount of money spent per graduation gift in 2007 was within this interval 98% of the time.
The confidence interval you compute depends on the data you have collected. If you repeat the experiment, your confidence interval would almost certainly be different.If multiple samples were drawn from the same population and a 98% Confidence intervals calculated for each sample, we would expect the population mean to be found within 98% of these Confidence intervals.