In: Statistics and Probability
How much money do people spend on graduation gifts? In 2007, a federation surveyed 2215 consumers who reported that they bought one or more graduation gifts that year. The sample was selected in a way designed to produce a sample representative of adult Americans who purchased graduation gifts in 2007. For this sample, the mean amount spent per gift was $55.25. Suppose that the sample standard deviation was $20. Construct a 98% confidence interval for the mean amount of money spent per graduation gift in 2007. (Round your answers to three decimal places.) PLEASE EXPLAIN IN STEPS
(_,_)
Interpret the interval.
We are confident that the mean amount of money spent per graduation gift in 2007 was within this interval 98% of the time.
We are confident that 98% of the amount of money spent per graduation gift in 2007 was within this interval.
We are 98% confident that the mean amount of graduation money spent was within this interval.
We are 98% confident that the mean amount of money spent per graduation gift in 2007 was within this interval.
Solution :
Given that,
Point estimate = sample mean = = 55.25
sample standard deviation = s = 20
sample size = n = 2215
Degrees of freedom = df = n - 1 = 2215 - 1 = 2214
At 98% confidence level
= 1 - 98%
=1 - 0.98 =0.02
/2
= 0.01
t/2,df
= t0.01,2214 = 2.328
Margin of error = E = t/2,df * (s /n)
= 2.328 * (20 / 2215)
Margin of error = E = 0.989
The 98% confidence interval estimate of the population mean is,
± E
= 55.25 ± 0.989
= ( 54.261, 56.239 )
We are 98% confident that the mean amount of money spent per graduation gift in 2007 was within this interval.