a 2.00 l container holds 4.00 moles of o2 and 2.70 moles of he at 293...

a 2.00 l container holds 4.00 moles of o2 and 2.70 moles of he at 293 k. What is the partial pressure of o2? He? what is the total pressure?

Solutions

Expert Solution

Ideal gas equation

PV = nRT where, P = atm pressure= ?

V = volume in Liter = 2 L

n = number of mole = 4.00 + 2.70 = 6.70

R = 0.08205L atm mol^-1 K^-1 =Proportionality constant = gas constant,

T = Temperature in K = 293 K

We can write ideal gas equation

P = nRT/V

Substitute value in above equation

P = 6.700.08205293 / 2 = 80.536 atm

Total pressure = 80.536 atm

total mole = 4.00 + 2.70 = 6.70

mole fraction of O₂ = 4/6.70 = 0.597

mole fraction of He = 2.70/6.70 = 0.403

P_i = X_i P where, P_i = partial pressure of indivisual gas, P = total pressure, X_i = mole fraction of indivisual gas

substiture value in above equation

Partial pressure of O₂ = 0.597 80.536 = 48.079992 atm

Partial pressure of He = 0.403 80.536 = 32.456008 atm

queen_honey_blossom answered 1 year ago

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