In: Math
Here is some data looking at people's salaries, their years of experience, and their average evaluation. Please cut and paste it into excel and run the following regression: Salary = b0 + b1*Experience + b2*Eval
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True/false. The eval score is a significant predictor of salary at the 5% level.
True
False
Solution:
In excel go to
Data>Data analysis>regression
you will get
SUMMARY OUTPUT | ||||||
Regression Statistics | ||||||
Multiple R | 0.804387228 | |||||
R Square | 0.647038813 | |||||
Adjusted R Square | 0.529385084 | |||||
Standard Error | 3167.333553 | |||||
Observations | 9 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 2 | 1.1E+08 | 55171176 | 5.4995181 | 0.043972469 | |
Residual | 6 | 60192011 | 10032002 | |||
Total | 8 | 1.71E+08 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | 54187.6859 | 3044.864 | 17.79642 | 2.023E-06 | 46737.17125 | 61638.2 |
Years of experience | 1206.385977 | 384.0964 | 3.140842 | 0.0200465 | 266.5359348 | 2146.236 |
Average evaluation | -624.0392499 | 589.5046 | -1.05858 | 0.3305343 | -2066.505 | 818.4265 |
For avergae evaluation
t=-1.05858
p=0.3305
p>0.05
Not significant predictor at 5% level of signifcance.
he eval score is NOT a significant predictor of salary at the 5% level.
FALSE