Question

In: Math

Here is some data looking at people's salaries, their years of experience, and their average evaluation....

Here is some data looking at people's salaries, their years of experience, and their average evaluation. Please cut and paste it into excel and run the following regression:

Salary = b0 + b1*Experience + b2*Eval

Salary Years of experience Average evaluation
$ 56,744.30 5 6.85
$ 49,875.12 0 2.92
$ 64,629.44 6 1.69
$ 53,148.67 2 1.89
$ 56,130.69 8 4.93
$ 57,246.71 4 5.87
$ 51,097.09 0 5.09
$ 50,303.00 0 6.42
$ 56,212.37 2 4.2

True/false. The eval score is a significant predictor of salary at the 5% level.

True

False

Solutions

Expert Solution

Solution:

In excel go to

Data>Data analysis>regression

you will get

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.804387228
R Square 0.647038813
Adjusted R Square 0.529385084
Standard Error 3167.333553
Observations 9
ANOVA
df SS MS F Significance F
Regression 2 1.1E+08 55171176 5.4995181 0.043972469
Residual 6 60192011 10032002
Total 8 1.71E+08
Coefficients Standard Error t Stat P-value Lower 95% Upper 95%
Intercept 54187.6859 3044.864 17.79642 2.023E-06 46737.17125 61638.2
Years of experience 1206.385977 384.0964 3.140842 0.0200465 266.5359348 2146.236
Average evaluation -624.0392499 589.5046 -1.05858 0.3305343 -2066.505 818.4265

For avergae evaluation

t=-1.05858

p=0.3305

p>0.05

Not significant predictor at 5% level of signifcance.

he eval score is NOT a significant predictor of salary at the 5% level.

FALSE


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