Calculate the pH and the equilibrium concentrations of HCO3- and CO32- in a 0.0514 M carbonic...

Calculate the pH and the equilibrium concentrations of HCO3- and CO32- in a 0.0514 M carbonic acid solution, H2CO3 (aq). For H2CO3, Ka1 = 4.2×10-7 and Ka2 = 4.8×10-11 pH = [HCO3-] = M [CO32-] = M

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Expert Solution

H2CO3 (aq) <---------------> H+ (aq) + HCO3- (aq)

0.0514 0 0

0.0514 - x x x

Ka1 = x^2 / 0.0514 - x

4.2 x 10^-7 = x^2 / 0.0514 - x

x = 1.47 x 10^-4

[H+] = 1.47 x 10^-4 M

pH = -log (1.47 x 10^-4)

pH = 3.83

[HCO3-] = 1.47 x 10^-4 M

[CO32-] = 4.80 x 10^-11 M

queen_honey_blossom answered 1 year ago

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