In: Chemistry
Calculate the theoretical yield of Cu(NH3)4SO4∙H2O (MW = 245.7g/mol) based on 10.0g of CuSO4∙5H2O (MW = 249.7g/mol).
The balanced chemical equation for the above reaction is
CuSO4∙5H2O + 4 NH3 ---> Cu(NH3)4SO4∙H2O + 4H2O
From the above equuation it was clear that 1 mole of CuSO4∙5H2O will form 1 mole of Cu(NH3)4SO4∙H2O
No. of moles of CuSO4∙5H2O reacted = weight / MW = 10 g / 249.7 g/mole = 0.040048 moles = No. of moles of Cu(NH3)4SO4∙H2O formed.
Hence, The theoretical yield of Cu(NH3)4SO4∙H2O in grams = No. of moles x Molecular weight
= 0.040048 mole x 245.7g/mol
= 9.84 g