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In: Chemistry

CuSO4·5H2O + 2NaC7H5O2 → Cu(C7H5O2)2·2H2O + Na2SO4 + 3H2O a) Determine the number of moles of...

CuSO4·5H2O + 2NaC7H5O2 → Cu(C7H5O2)2·2H2O + Na2SO4 + 3H2O

a) Determine the number of moles of CuSO4·5H2O contained in 2.00 g of CuSO4·5H2O.

b)Calculate the mass of NaC7H5O2 you will need to react "completely" with the 2.00 g of CuSO4·5H2O.

Solutions

Expert Solution

Ans a)

Molar mass of CuSO4·5H2O is 249.69 g/mol. The number of moles of CuSO4·5H2O in 2.0g of CuSO4·5H2O can be calculated as follows:

Number of moles of CuSO4·5H2O = Weight of CuSO4·5H2O / molar mass of CuSO4·5H2O

Number of moles of CuSO4·5H2O = (2.00 g) / (249.69 g/mol)

Number of moles of CuSO4·5H2O = 0.00801 mol

Ans b)

The balanced equation of reaction of CuSO4·5H2O and NaC7H5O2 can be written as follows:

CuSO4·5H2O + 2NaC7H5O2 → Cu(C7H5O2)2·2H2O + Na2SO4 + 3H2O

Thus, one mole of CuSO4·5H2O reacts with two moles of NaC7H5O2.

Therefore, 2.00g of CuSO4·5H2O (0.00801 mol) will react with (0.00801 x 2) mol of NaC7H5O2. Thus, mass of (0.00801 x 2) mol of NaC7H5O2 can be calculated as follows:

Mass of (0.00801 x 2) mol of NaC7H5O2 = (0.00801 x 2) mol x molar mass of NaC7H5O2

Mass of (0.00801 x 2) mol of NaC7H5O2 = (0.00801 x 2) mol x 144.10 g/mol

Mass of (0.00801 x 2) mol of NaC7H5O2 = 2.31 g

Thus, the mass of NaC7H5O2 needed to react "completely" with the 2.00 g of CuSO4·5H2O is 2.31 g.


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