In: Chemistry
mass of water = 250 g
mass of butter = 2.31 g
molar mass of butter = 891.485 g/mol
Specific heat = 4.184 J/g.c
Heat released = Heat absorbed by water
= mass * specific heat * temperature change of water
= 250 * 4.184*( 210-17.05)
= 201825 J
Moles of butter = mass / molar mass of butter
= 2.31 / 891.485
= 0.00259 mol
H = -heat released / moles of butter
= - 201825 / 0.00259
= - 7.79 * 10^7 J / mol
H = -7.79 * 10^4 kJ / mol