Question

In: Chemistry

Given that the heat of fusion of water is -6.02 kJ/mol, that the heat capacity of...

Given that the heat of fusion of water is -6.02 kJ/mol, that the heat capacity of H2O(l) is 75.2 J/mol⋅K and that the heat capacity of H2O(s) is 37.7 J/mol⋅K, calculate the heat of fusion of water at -14 ∘C.

I feel like I should be able to get this problem but something is just not clicking. Thank you for your help!

Solutions

Expert Solution

Heat of fusion of water

Generally we calculate heat of fusion at 0 °C

H2O(l) <====è H2O(s)

But here water is supercooled to -14 °C

H(fusion, -14 °C) = H(fusion, 0 °C) + [Cp(l)-Cp(s)]14 °C

                                    = -6.02 Kj/mol +[75.2-37.7]14

                                    =-6.02 kJ/mol+525 J/mol

                                    =-6.02 kJ/mol+0.525 kJ/mol

                                    =-5.495 kJ/mol


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