In: Statistics and Probability
3. Following data on adjusted income and reasonable itemized deduction amount of 1040 Form is published by IRS. (20 points)
Adjusted Gross Income ($1000) in 1040 |
Reasonable itemized reduction amount ($1000) |
22 |
9.6 |
27 |
9.6 |
32 |
10.1 |
48 |
11.1 |
65 |
13.5 |
85 |
17.7 |
120 |
25.5 |
ANSWER::
3Q)
Que.a
Predictor X = adjusted income
Response Y = Reasonable itemized deduction amount
In order to solve this question I used R software.
R codes and output:
> x=c(22,27,32,48,65,85,120)
> y=c(9.6,9.6,10.1,11.1,13.5,17.7,25.5)
> fit=lm(y~x)
> summary(fit)
Call:
lm(formula = y ~ x)
Residuals:
1 2 3 4 5 6 7
1.3744 0.5679 0.2613 -1.3196 -1.6619 -0.6881 1.4660
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 4.67675 1.03339 4.526 0.006251 **
x 0.16131 0.01568 10.285 0.000149 ***
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 1.372 on 5 degrees of freedom
Multiple R-squared: 0.9549, Adjusted R-squared: 0.9458
F-statistic: 105.8 on 1 and 5 DF, p-value: 0.0001493
> plot(x,y)
> abline(fit)
Que. b
Least square equation,
Y = 4.67675 + 0.16131 X
Que.c
Almost all points lie close to regression line. Hence regression line does a good job to describe the relationship.
Que.d
Taxpayer who earn $52500 (X = 52.5), estimated reasonable itemized reduction amount is,
Y = 4.67675 + 0.16131 X
Y = 4.67675 + 0.16131 (52.5)
Y = 13.145525
Que.e
Standard error of estimate = 1.372
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