Question

In: Statistics and Probability

3. Following data on adjusted income and reasonable itemized deduction amount of 1040 Form is published...

3. Following data on adjusted income and reasonable itemized deduction amount of 1040 Form is published by IRS. (20 points)

Adjusted Gross Income ($1000) in 1040

Reasonable itemized reduction amount ($1000)

22

9.6

27

9.6

32

10.1

48

11.1

65

13.5

85

17.7

120

25.5

  1. Which variable is the predictor (X) and which is the response (Y)?
  2. Find the least-square regression line y=a+bx
  3. Plot the data and your least-square line in one graph. Do you think that the regression line does a job to describe the relationship?
  4. What is the estimated reasonable itemized reduction amount for all the taxpayers who earn $52,500 a year? If John makes $52,500 and claim $20,400 itemized reduction, will IRS audit his tax return?
  5. Compute the standard error of estimate Sy,x for the least-square regression.

Solutions

Expert Solution

ANSWER::

3Q)

Que.a
Predictor X = adjusted income

Response Y = Reasonable itemized deduction amount

In order to solve this question I used R software.

R codes and output:

> x=c(22,27,32,48,65,85,120)
> y=c(9.6,9.6,10.1,11.1,13.5,17.7,25.5)
> fit=lm(y~x)
> summary(fit)

Call:
lm(formula = y ~ x)

Residuals:
1 2 3 4 5 6 7
1.3744 0.5679 0.2613 -1.3196 -1.6619 -0.6881 1.4660

Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 4.67675 1.03339 4.526 0.006251 **
x 0.16131 0.01568 10.285 0.000149 ***
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 1.372 on 5 degrees of freedom
Multiple R-squared: 0.9549, Adjusted R-squared: 0.9458
F-statistic: 105.8 on 1 and 5 DF, p-value: 0.0001493

> plot(x,y)
> abline(fit)

Que. b

Least square equation,

Y = 4.67675 + 0.16131 X

Que.c

  

Almost all points lie close to regression line. Hence regression line does a good job to describe the relationship.

Que.d

Taxpayer who earn $52500 (X = 52.5), estimated reasonable itemized reduction amount is,

Y = 4.67675 + 0.16131 X

Y = 4.67675 + 0.16131 (52.5)

Y = 13.145525

Que.e

Standard error of estimate = 1.372

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