Question

Separation of Mixtures Experiment

How do I calculate #6 the saturated NaCl solution and #7 the mass of sodium chloride from the information below?

1. Mass of evaporating dish: 54.3184g

2. Mass of dish and sodium chloride: 61.1048g

3. Mass of dish and sodium chloride (1st heating): 56.0387g

4. Mass of dish and sodium chloride (2nd heating): 56.0293g

5. Mass of dish and sodium chloride (3rd heating if necessary): N/A

6. Mass of saturated sodium chloride solution: ___

7. Mass of sodium chloride: ___

Also, can you please confirm that the following formulas are correct?

Mass % of NaCl in saturated solution: mass% = [(mass of NaCl) / (mass of NaCl + mass of saturated NaCl)]

Percent deviation between your value and an accepted literature value of 26.4%: % deviation = [|26.4 - my value| / 26.4] x 100%

Answer 1

1)Given mass of dish and sodium chloride (mass of saturated NaCl solution +mass of dish): 61.1048g

Mass of evaporating dish: 54.3184g

Threfore the mass of saturated solution of NaCl is: ( 61.1048g-54.3184g) = 6.7868g

2)Mass of dish and sodium chloride is : 56.0293g

Mass of evaporating dish: 54.3184g

mass of sodium chloride = (56.0293g-54.3184g) = 1.7109g

mass% = [(mass of NaCl) / (mass of NaCl + mass of saturated NaCl)]

             = 1.7109g/( 1.7109g+6.7868g)

             = 0.201

             =20.1%

% deviation = [|26.4 - my value| / 26.4] x 100%

                     = (26.4-20.1)/26.4] x 100%

                     = 23.86