In: Chemistry
Separation of Mixtures Experiment
Given information:
1. Mass of evaporating dish: 54.3184g
2. Mass of dish and sodium chloride: 61.1048g
3. Mass of dish and sodium chloride (1st heating): 56.0387g
4. Mass of dish and sodium chloride (2nd heating): 56.0293g
5. Mass of dish and sodium chloride (3rd heating if necessary): N/A
6. Mass of saturated sodium chloride solution: ___
7. Mass of sodium chloride: ___
Question 1) How do I calculate the saturated NaCl solution?
Question 2) How do I calculate the mass of sodium chloride?
Also, can you please confirm that the following formulas are correct?
Mass % of NaCl in saturated solution: mass% = [(mass of NaCl) / (mass of NaCl + mass of saturated NaCl)]
Calculate percent deviation between your value and an accepted literature value of 26.4%: % deviation = [|26.4 - my value| / 26.4] x 100%
1) Mass of saturated NaCl solution = Mass of NaCl+Mass of NaCl (1st heating )+Mass of NaCl (2nd heating)
As saturated solution is the maximum concentration of solute in the solution
Mass of NaCl = Mass of dish and sodium chloride - Mass of evaporating dish = 61.1048g-54.3184g
Mass of NaCl = 6.7864g
Mass of NaCl (1st Heating)= Mass of dish and sodium chloride(1st heating) - Mass of evaporating dish
Mass of NaCl (1st Heating)= 56.0387g - 54.3184g = 1.7203g
Mass of NaCl (2nd Heating)= Mass of dish and sodium chloride(2nd heating) - Mass of evaporating dish
Mass of NaCl (1st Heating)= 56.0293g - 54.3184g = 1.7109g
Now Mass of saturated NaCl solution = Mass of NaCl+Mass of NaCl (1st heating )+Mass of NaCl (2nd heating)
Mass of saturated NaCl solution = 6.7864g + 1.7203g +1.7109g = 10.2176g
2) Mass of NaCl = Mass of dish and sodium chloride - Mass of evaporating dish = 61.1048g-54.3184g
Mass of NaCl = 6.7864g
Yes the provided formula is correct
Mass% = [(Mass of NaCl )/ (Mass of NaCl + Mass of Saturated NaCl)]
Mass% = [(6.7864g)/(10.2176g)] = 0.6641*100% = 66.41%
% Deviation = [(my value - literature value)/literature value]*100%
% Deviation = [(66.41-26.4)/26.4]*100% = (40.01/26.4)*100% = 151.55%