What is the [OH-] of a 1x10-3 M solution of NH4Cl?

Expert Solution

NH3 , Kb value = 1.8 x 10^-5

Ka = Kw / Kb = 1.0 x 10^-14 / 1.8 x 10^-5

Ka = 5.55 x 10^-10

NH4+ -----------------------> NH3 + H+

10^-3 0 0

10^-3-x x x

Ka = x^2 / 10^-3 -x

5.55 x 10^-10 = x^2 / 10^-3 -x

x^2 + 5.55 x 10^-10 x - 5.55 x 10^-13 = 0

x = 7.44 x 10^-7

[H+] = 7.44 x 10^-7 M

[OH-] = Kw [H+]

= 1.0 x 10^-14 / 7.44 x 10^-7

= 1.34 x 10^-8 M

[OH-] = 1.34 x 10^-8 M

queen_honey_blossom answered 1 year ago

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