In: Chemistry
Consider a buffer solution that is 0.50 M in NH3 and 0.20 M in NH4Cl . For ammonia, pKb=4.75 . Calculate the pH of 1.0 L upon addition of 0.050 mol of solid NaOH to the original buffer solution.
1)
we have below equation to be used:
This is Henderson–Hasselbalch equation
pOH = pKb + log {[conjugate acid]/[base]}
= 4.75+ log {0.2/0.5}
= 4.352
we have below equation to be used:
PH = 14 - pOH
= 14 - 4.3521
= 9.65
Answer: 9.65
2)
mol of NaOH added = 0.05 mol
NH4+ will react with OH- to form NH3
Before Reaction:
mol of NH3 = 0.5 M *1.0 L
mol of NH3 = 0.5 mol
mol of NH4+ = 0.2 M *1.0 L
mol of NH4+ = 0.2 mol
after reaction,
mol of NH3 = mol present initially + mol added
mol of NH3 = (0.5 + 0.05) mol
mol of NH3 = 0.55 mol
mol of NH4+ = mol present initially - mol added
mol of NH4+ = (0.2 - 0.05) mol
mol of NH4+ = 0.15 mol
since volume is both in numerator and denominator, we can use mol instead of concentration
we have below equation to be used:
This is Henderson–Hasselbalch equation
pOH = pKb + log {[conjugate acid]/[base]}
= 4.75+ log {0.15/0.55}
= 4.186
we have below equation to be used:
PH = 14 - pOH
= 14 - 4.1857
= 9.81
Answer: pH is 9.81