Determine the [OH−] of a solution that is 0.120 M in CO32−.

Expert Solution

As the above reaction is given by the following reaction

CO32- + H2O ----> HCO3- + OH -

Kc = [HCO3- ] [OH -] / [ CO32- ]

5.6*10^-11 = x² / 0.120 - x

x² +5.6*10^-11x - 6.72 *10^-12

we solve using quadratic equation to find out value of x

x= - b +- b2 -4ac

x= - 5.6*10^-11+- (5.6*10^-11)² - 4 (1) (6.72 *10^-12) / 2(1)

=-5.6*10^-11 +- 31.36 * 10^-22 - 26.88 10^-12) / 2(1) ( neglect 31.36 * 10^-22 in compare to 26.88 10^-12 )

= - 5.6*10^-11 + 26.88* 10^-12 ) / 2(1) ( neglect 5.6*10^-11 in compare to 5.184 *10^-6 )

= -5.6*10^-11+ 5.184 * 10^-6 / 2

we get our concentration of OH- ion as

[OH] = 2.592 *10^-6

queen_honey_blossom answered 2 years ago

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