Calculate the pH of a solution composed of 0.50 M NH3 and 0.20 M NH4Cl. Kb...

Calculate the pH of a solution composed of 0.50 M NH3 and 0.20 M NH4Cl. Kb NH3 = 1.8 x 10-5

Expert Solution

PKb = -logKb

= -log1.8*10^-5

= 4.75

POH = PKb + log[NH4Cl]/[NH3]

= 4.75 + log0.2/0.5

= 4.75 -0.3979

= 4.3521

PH = 14-POH

= 14-4.3521 = 9.6479 >>>> answer

queen_honey_blossom answered 2 years ago

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