In: Chemistry
What is the pH of a 0.1911 M HCl solution? What is the (OH-]?
Concentration of HCl = 0.1911 M
The dissociation reaction of HCl
HCl = H+ + Cl-
[HCl] = [H+] = 0.1911 M
pH = - log [H+] = - log (0.1911)
pH = 0.7187
pOH = 14 - pH = 14 - 0.7187 = 13.2813
pOH = - log [OH-]
13.2813 = - log [OH-]
[OH-] = 10^(-13.2813) = 5.2324 x 10^-14 M