Question

In: Chemistry

Atomic chlorine is produced under ozone-hole conditions by the photodissociation of Cl2. Given that Cl2 gas...

Atomic chlorine is produced under ozone-hole conditions by the photodissociation of Cl2. Given that Cl2 gas is the most stable form of the element, and that the ΔHfo for atomic chlorine is +121.7 kJ mol-1, calculate the maximum wavelength of light that can dissociate diatomic chlorine into the monoatomic form. Does this wavelength correspond to the UVA or UVB region of the wavelength spectrum?

Solutions

Expert Solution

ΔHfo for atomic chlorine is +121.7 kJ mol-1

so that , DH0 dissociation of Cl2 = 121.7*2 = +243.4 Kj/mol

1 Cl2 molecule required energy = 243.4*10^3/(6.023*10^23) = 4.04*10^-19 joule

suitable wavelength (l) = hc/E = (6.625*10^-34*3*10^8)/(4.04*10^-19)

                                                  = 4.92*10^-7 m

                                                   = 492 nm

                  suitable light = visible region.


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