Chlorine gas reacts with fluorine gas to form chlorine trifluoride. Cl2(g)+3F2(g)→2ClF3(g) A 2.15 L reaction vessel,...

Chlorine gas reacts with fluorine gas to form chlorine trifluoride. Cl2(g)+3F2(g)→2ClF3(g) A 2.15 L reaction vessel, initially at 298 K, contains chlorine gas at a partial pressure of 337 mmHg and fluorine gas at a partial pressure of 882 mmHg. Identify the limiting reactant and determine the theoretical yield of ClF3 in grams.

Expert Solution

Cl2 + 3 F2 ------------------------> 2 ClF3

1 3 2

337 882

limiting reagent is F2 . because the ratio of pressure of F2 882 / 3 = 294 less than that of Cl2 pressure ratio. so

limiting reagent is F2

pressure of ClF3 formed = 882 x 2 / 3

= 588 mmHg

pressure = 588 mmHg = 0.774 atm

volume = 2.15 L

temperature = 298 K

P V = n R T

0.774 x 2.15 = n x 0.0821 x 298

n = 0.06798

mass of ClF3 = 0.06798 x 92.45 = 6.29 g

theoretical yield of ClF3 = 6.29 g

queen_honey_blossom answered 2 years ago

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