Question

A concentrated solution of H2SO4 has a molarity of 15.5 M, and a density of 1.760 g/ml

A. How many grams of H2SO4 are in a liter of the solution?

B. What is the total mass of a liter of the solution?

C. How many grams of water are in a liter of the solution?

D. What is the mole fraction of the H2SO4 in this mix?

E. What is the molality of the H2SO4?

Answer 1

A) molarity = 15.5 M

it means in 1 litre 15.5 moles are present

molar mass of H2SO4 = 98 g/mol

moles = mass / molar mass

15.5 = mass / 98

mass = 15.5 x 98 = 1519 g

1519 g present in 1 litre solution

B) for 1 ml ------------------> 1.760 g solution

    for 1000ml (1 L) -----------------. 1.760 x 1000 = 1760 g solution

so total mass = 1760 g

C) water mass = solution mass - H2SO4 mass

                         = 1760 - 1519

                          = 241 g

D) moles of H2SO4 = 15.5

   moles of H2O = mass / molar mass

                          = 241 / 18

                          = 13.39

total moles = H2O moles + H2SO4 moles

                   = 13.39 + 15.5

                    = 28.89

mole fraction of H2SO4 = moles of H2SO4 / total moles

                                      = 15.5 / 28.89

                                     = 0.54

E) molarity of H2SO4 = 15.5 M