24.56 mL of a H2SO4 solution of unknown molarity is titrated to the equivalence point with...

24.56 mL of a H2SO4 solution of unknown molarity is titrated to the equivalence point with 19.3mL of a 0.45 M KOH solution to the equivalence point. What is the concentration of the acid solution? (please show work and answer in correct sig figs and scientific notation)

Expert Solution

H2So4 (aq) + 2KOH (aq) -------------------> K2So4(aq) + 2H2O(l)

1 mole 2 moles

H2So4 KOH

M1 = M2 = 0.45M

V1 = 24.56ml V2 = 19.3ml

n1 = 1 n2 = 2

M1V1/n1 = M2V2/n2

M1 = M2V2n1/V1n2

= 0.45*19.3*1/24.56*2 = 0.18 M

The conc of H2So4 is 0.18M = 1.8*10^-1M

queen_honey_blossom answered 2 years ago

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