how many hydrogen atoms are in 345.3 grams of iron (III) hydrogen phosphate?

Expert Solution

molecular formula of iron(lll) hydrogen phosphate = Fe₂(HPO₄)₃

molar mass of iron(lll) hydrogen phosphate = 399.6279 gm / mole

molar mass of hydrogen = 1.00794 gm / mole thus molar mass of 3 hydrogen = 3.02382 gm

in molecule of iron (lll) hydrogen phosphate contain 3 atom of hydrogen

that mean in 399.6279 gm of iron(lll) hydrogen phosphate contain 3.02382 gm of Hydrogen then 345.3 gm of iron(lll)hydrogen phosphate contain = 345.3 3.02382 / 399.6279 = 2.6127 gm of hydrogen

molar mass of hydrogen = 1.00794 gm / mole then 2.6127 gm of hydrogen = 2.6127 / 1.00794 = 2.592 mole of hydrogen.

1 mole of substance contain 6.022 10²³ atom then 2.592 gm contain

2.592 6.022 10²³ = 1.5609024 10²⁴ atom of hydrogen

345.3 gm of iron(lll) hydrogen phosphate contain = 1.5609024 10²⁴ atom of hydrogen

queen_honey_blossom answered 3 years ago

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