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Iron reacts with chlorine gas to form iron (III) chloride. How many grams of iron(III) chloride...

Iron reacts with chlorine gas to form iron (III) chloride. How many grams of iron(III) chloride are formed from 112g of iron?

Wondering if I did this right!

First balance: 3Fe + Cl ---> FeCl3 or 3Fe + 3Cl ---> FeCl3 *Not Sure*

Second Convert grams to mols: 112g/Fe to Mols = 2 mol/fe

Third Convert mols to gram: 2 mol/Fe * 162.204g/FeCl3 / 3 mol/Fe = 108.136 g/FeCl/3 round 108grams/FeCl3

Please do and let me know if this correct! Not sure if its the correct answer. All done in Dimensional Analysis

Expert Solution

First let us balance the reaction

2Fe + 3Cl2 --> 2FeCl3

weight of iron used for above reaction = 112 grams of iron

Molar mass of iron =56

Moles of iron formed = weight of iron / molar mass of iron = 112/56 = 2 moles of iron

Now let us calculate grams of iron chloride formed

From reaction stoichiometry

2 moles of iron = 2 moles of iron chloride

Hence moles of iron chloride = moles of iron = 2 moles

Molar mass of iron chloride =162.2 grams/mole

Weight of iron chloride = moles of iron chloride * molar mass of iron chloride

= 2 *162.2 = 324.4 grams

Grams of iron chloride formed in the above reaction = 324.4 grams

queen_honey_blossom answered 2 years ago

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