How many atoms are there in 79.3 g of potassium dihydrogen phosphate (KH2PO4)?

Expert Solution

Weight of postassium dihydrogen phosphate ( KH₂PO₄) = 79.3 grams

Molecular weight of potassium dihydrogen phosphate ( KH₂PO₄) =39+2(1)+31+16(4)=136 g/mole

Hence number of moles of potassium dihydrogen phosphate ( KH₂PO₄)

=Weight of potassium dihydrogen phosphate ( KH₂PO₄)/molecular weight of potassium dihydrogen phosphate (KH₂PO₄)

=79.3/136 =0.583 moles of KH₂PO₄

Now to calculate the number of atomes present in 79.3 grams of KH₂PO₄ we do the following.

We know that number of atomes in 1 moles = 6.023*10²³

There for number of atoms in 0.583 moles of KH₂PO₄=0.583*6.023*10²³=3.5119*10²³ atoms

Hence number of atoms in 79.3 g of KH₂PO₄ is 3.5119*10²³ atoms

queen_honey_blossom answered 2 years ago

Design a procedure to prepare 75 ml of 0.10 M potassium dihydrogen phosphate solution (KH2PO4) and...

Design a procedure to prepare 75 ml of 0.10 M potassium dihydrogen phosphate solution (KH2PO4) and 75 ml of 0.10 M dipotassium hydrogen phosphate solution (K2HPO4) from the solids. (Hint: What mass of the above solids is required to make 75 ml of a 0.10 M solution?)

How many moles of anion are in 3.262 kg of potassium phosphate? How many moles of...

How many moles of anion are in 3.262 kg of potassium phosphate? How many moles of ions are in 3.262 kg of potassium phosphate?

Prepare 100mL of a 0.1M potassium phosphate buffer of pH 6.5. You have K2HPO4 and KH2PO4...

Prepare 100mL of a 0.1M potassium phosphate buffer of pH 6.5. You have K2HPO4 and KH2PO4 in solid/salt form available to mix with water to create this buffer. Final answer must include how many grams of each salt to mix with how many mL of water to prepare the buffer. I started this problem and got as far as using the Henderson-Hasselbalch equation and that the ratio of [HPO42-] to [H2PO4-] is 0.48 moles to 1 mole.

The following chemicals have the indicated formula weights: Sucrose -- 342.3g/mol Potassium dihydrogen phosphate (KH2P04) --...

The following chemicals have the indicated formula weights: Sucrose -- 342.3g/mol Potassium dihydrogen phosphate (KH2P04) -- 136.09g/mol You also have the following solutions already made: 20% SDS, 5M NaCl and 10X TAE List the steps to make the following buffers (be specific and show calculations): a. 1 liter of a solution containing: 0.5 M sucrose, 0.05 M NaCl, 0.02 M KH2PO4. b. 100 ml of 10% SDS, 1M NaCl. c. 40 ml 0.5% agarose in 1X TAE solution (calculate for...

how many hydrogen atoms are in 345.3 grams of iron (III) hydrogen phosphate?

-How many atoms are in 4.39 g of CO2? -How many molecules are there in 8.0...

-How many atoms are in 4.39 g of CO2? -How many molecules are there in 8.0 g of ozone, O3? -How many sulfur atoms are there in 21.0 g of Al2S3? -How many sulfur atoms are present in 25.6 g of Al2(S2O3)3? -Determine the number of moles of aluminum in 96.7 g of Al.

How many oxygen atoms are in 3.70 g of quartz?

How many total atoms are in 0.850 g of P2O5?

1) How many atoms are there in 51.3 g of barium chloride (BaCl2)? 2) How many...

1) How many atoms are there in 51.3 g of barium chloride (BaCl2)? 2) How many moles of carbon monoxide (CO) are in 29.3 g of the compound? 3) What is the formula for copper(II) phosphate? Capitalization and punctuation count? 4) How many atoms of phosphorus are in 2.90 mol of copper(II) phosphate? 5) How many moles of N are in 0.191 g of N2O? 6) A sample of C3H8 has 7.68 × 1024 H atoms. How many carbon atoms...

How many grams of nickel (II) phosphate (366 g/mol) will precipitate if excess sodium phosphate is...

How many grams of nickel (II) phosphate (366 g/mol) will precipitate if excess sodium phosphate is added to 1.20 L of 0.684 M nickel acetate? (a) 100 g (b) 200 g (c) 300 g (d) 600 g (e) 167 g

Question