In: Statistics and Probability
The following data are given for a two-factor ANOVA with two treatments and three blocks.
Treatment | ||
Block | 1 | 2 |
A | 43 | 31 |
B | 33 | 22 |
C | 46 | 36 |
Using the 0.05 significance level conduct a test of hypothesis
to determine whether the block or the treatment means
differ.
State the null and alternate hypotheses for treatments.
State the decision rule for treatments. (Round your answer to 1 decimal place.)
State the null and alternate hypotheses for blocks. (Round your answer to 1 decimal place.)
Also, state the decision rule for blocks.
d & e. Compute SST, SSB, SS total, and SSE and complete an ANOVA table. (Round your SS, MS values to 3 decimal places and F value to 2 decimal places.)
Give your decision regarding the two sets of hypotheses.
Treatment
Block
Alternative Hypothesis, H1: At least one block has a significantly different mean.
The P-value for the treatment is 0.003 and less than 0.05 level of significance. Hence, we can reject the null hypothesis and conclude that the treatment means differ at the 0.05 level of significance.
The P-value for the block is 0.005 and less than 0.05 level of significance. Hence, we can reject the null hypothesis and conclude that the block means differ at the 0.05 level of significance.