Question

In: Statistics and Probability

Apply the techniques of two-way ANOVA to a data sample split into eight treatments with total...

Apply the techniques of two-way ANOVA to a data sample split into eight treatments with total degrees of freedom, df = 47, testing at the 2.5% level of significance. The Sum of Squares for Treatments is 42; the Mean Square for Blocks is 9, and the Mean Square for Error is 3.

SS df MS F test Stats
Treatments #1 #5 #9 #12
Blocks #2 #6 #10 #13
Error #3 #7 #11 XXXXXXX
Total #4 #8 XXXXXXX XXXXXXX

#14: What is the F critical for treatments, rounding to the nearest ten-thousandths? [COMMENTS & HINTS: It is a number between zero and ten. Enter this answer as #.####]

#15: What is the F critical for blocks, rounding to the nearest ten-thousandths? [COMMENTS & HINTS: It is a number between zero and ten. Enter this answer as #.####]

#16: What is the most appropriate technical conclusion for treatments, based on the available evidence and testing at the indicated level of significance? {Select the best response.}

a) The researcher would highly reject the unidentified null hypothesis.    b) The researcher would reject the unidentified null hypothesis. c) The researcher would marginally reject the unidentified null hypothesis.    d) The researcher would highly fail to reject the unidentified null hypothesis. e) The researcher would fail to reject the unidentified null hypothesis. f) The researcher would marginally fail to reject the unidentified null hypothesis.

#17: What is the most appropriate technical conclusion for blocks, based on the available evidence and testing at the indicated level of significance? {Select the best response.}

a) The researcher would highly reject the unidentified null hypothesis. b) The researcher would reject the unidentified null hypothesis. c) The researcher would marginally reject the unidentified null hypothesis.    d) The researcher would highly fail to reject the unidentified null hypothesis. e) The researcher would fail to reject the unidentified null hypothesis.    f) The researcher would marginally fail to reject the unidentified null hypothesis.

#18: What is the total sample size, n?

#19: What is the p-value, reported to four decimal places, for treatments?

#20: What is the p-value, reported to four decimal places, for blocks?

#21: What is the number of blocks?

Solutions

Expert Solution

SOLUTION

The completed table is,

Source SS df MS F
Treatments 42 7 6 2
Blocks 45 5 9 3
Error 105 35 3
Total 192 47

df for Treatments = Number of treatments - 1 = 8 - 1 = 7

Total number of observations = df Total + 1 = 47 + 1 = 48

Number of blocks = Total number of observations / Number of treatments = 48 / 8 = 6

df for Blocks = Number of blocks - 1 = 6 - 1 = 5

df for Error = df Total - (df treatments + df Blocks) = 47 - (7 + 5) = 35

SS = MS * df for Blocks , Error

SS Total = SS Treatments + SS Block + SS error = 42 + 45 + 105 = 192

MS Treatments = SS Treatments / df Treatments = 42 / 7 = 6

F = MS / MS Error for Treatments and Blocks

14.

For Treatments,

Numerator df = df Treatments = 7

Denominator df = df Error = 35

Critical value of F at df = 7, 35 and 2.5% level of significance is 2.6755

15.

For Blocks,

Numerator df = df Blocks = 5

Denominator df = df Error = 35

Critical value of F at df = 5, 35 and 2.5% level of significance is 2.9557

16.

P-value = P(F > 2, df = 7,35) = 0.0831

Since F for Treatments (2) is less than the critical value of 2.6755, and p-value is under 0.1 but greater than 0.025,

e) The researcher would fail to reject the unidentified null hypothesis

17.

P-value = P(F > 3, df = 5,35) = 0.0234

Since F for Blocks (3) is greater than the critical value of 2.9557, and p-value is just less than 0.025,

c) The researcher would marginally reject the unidentified null hypothesis

18.

Total sample size, n = df Total + 1 = 47 + 1 = 48

19.

P-value for treatments,

P-value = P(F > 2, df = 7,35) = 0.0831

20.

P-value for blocks,

P-value = P(F > 3, df = 5,35) = 0.0234

21.

Number of blocks = 6 (Calculated above)


Related Solutions

Discuss the applications of ANOVA (One-Way ANOVA, Two-Way ANOVA) and regression techniques in the context of...
Discuss the applications of ANOVA (One-Way ANOVA, Two-Way ANOVA) and regression techniques in the context of e-commerce firms like Amazon, Flipkart etc.
Purpose: To learn how to analyze data from a two-way Anova and apply the results to...
Purpose: To learn how to analyze data from a two-way Anova and apply the results to a research scenario. Instructions: Enter the data below into the SPSS Data Editor (download the .sav file from D2L to check your work). Run a two-way analysis of variance and create a line graph depicting the group means. Use your results to answer the questions below, and then submit in D2L. Research Scenario: You have been raising Bombina orientalis, or Oriental fire-bellied toads, and...
How do multiple comparison techniques differ when we do two-way ANOVA as compared to one-way ANOVA?
How do multiple comparison techniques differ when we do two-way ANOVA as compared to one-way ANOVA?
The following data was collected for a two -factor ANOVA with three treatments and two blocks....
The following data was collected for a two -factor ANOVA with three treatments and two blocks. Treatment 1 2 3 Block A 8 12 20 B 10 14 18 a) Complete an ANOVA table. b) State the null and alternative hypotheses for treatments. c) State the null and alternative hypotheses for the blocks. d) Using the 0.05 significance level perform the test and indicate your decision for parts b and c.
The following data are given for a two-factor ANOVA with two treatments and three blocks.   ...
The following data are given for a two-factor ANOVA with two treatments and three blocks.    Treatment Block 1 2 A 43 31 B 33 22 C 46 36    Using the 0.05 significance level conduct a test of hypothesis to determine whether the block or the treatment means differ. State the null and alternate hypotheses for treatments. State the decision rule for treatments. (Round your answer to 1 decimal place.)    State the null and alternate hypotheses for blocks....
The following data are given for a two-factor ANOVA with two treatments and three blocks.   ...
The following data are given for a two-factor ANOVA with two treatments and three blocks.    Treatment Block 1 2 A 46 33 B 30 21 C 46 30    Using the 0.05 significance level conduct a test of hypothesis to determine whether the block or the treatment means differ. State the null and alternate hypotheses for treatments. State the decision rule for treatments. (Round your answer to 1 decimal place.)    State the null and alternate hypotheses for blocks....
The following data are given for a two-factor ANOVA with two treatments and three blocks.   ...
The following data are given for a two-factor ANOVA with two treatments and three blocks.    Treatment Block 1 2 A 43 35 B 31 20 C 40 36    Using the 0.05 significance level conduct a test of hypothesis to determine whether the block or the treatment means differ. State the null and alternate hypotheses for treatments. State the decision rule for treatments. (Round your answer to 1 decimal place.)    State the null and alternate hypotheses for blocks....
The following data are given for a two-factor ANOVA with two treatments and three blocks.   ...
The following data are given for a two-factor ANOVA with two treatments and three blocks.    Treatment Block 1 2 A 43 31 B 33 22 C 46 36    Using the 0.05 significance level conduct a test of hypothesis to determine whether the block or the treatment means differ. State the null and alternate hypotheses for treatments. State the decision rule for treatments. (Round your answer to 1 decimal place.)    State the null and alternate hypotheses for blocks....
The following data are given for a two-factor ANOVA with two treatments and three blocks. Treatment...
The following data are given for a two-factor ANOVA with two treatments and three blocks. Treatment Block 1 2 A 42 32 B 33 20 C 48 39 Using the 0.05 significance level conduct a test of hypothesis to determine whether the block or the treatment means differ. State the null and alternate hypotheses for treatments. State the decision rule for treatments. (Round your answer to 1 decimal place.) State the null and alternate hypotheses for blocks. (Round your answer...
The following data are given for a two-factor ANOVA with two treatments and three blocks. Treatment...
The following data are given for a two-factor ANOVA with two treatments and three blocks. Treatment Block 1 2 A 46 31 B 37 26 C 44 35 Using the 0.05 significance level conduct a test of hypothesis to determine whether the block or the treatment means differ. a. State the null and alternate hypotheses for treatments.   H0 (Click to select)The standard deviations are different.The means are the same.The standard deviations are the same.The means are different.   H1 (Click to...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT