Look at the equation below. What is the acid on the left-hand side of the equation?...

Look at the equation below. What is the acid on the left-hand side of the equation?

?+NaOH --> NaCH3COO+H₂O

None of the other answers is correct.

H₂O

CH₃COOH

Question 43

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What is the conjugate base in the equation shown below?

CH₃COOH+H₂O ---> CH₃COO^- + H₃O⁺

H₃O⁺

None of the other answers is correct.

CH₃COO^-

Solutions

Expert Solution

1) first reaction is acid-base neutralization reaction in which salt and water is formed.

2) second reaction, when an acid is loses a proton, the residual part of it has a tendency to regain the proton . therefore it behaves as a base .

such pairs of substances which can be formed from one another by loss or gain of protons

are known as conjugate acid-base pairs

queen_honey_blossom answered 1 year ago

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