In: Statistics and Probability
An experiment was conducted to see the effectiveness of two
antidotes to three different doses of a toxin. The antidote was
given to a different sample of participants five minutes after the
toxin. Thirty minutes later the response was measured as the
concentration in the blood. What can the researchers conclude with
an α of 0.01?
Dose | |||
Antidote | 5 | 10 | 15 |
1 | 0.6 6.5 1.1 |
2.1 1.5 2.4 |
3.1 4.1 5.9 |
2 | 1.1 1.2 1.1 |
1.7 1.3 1.5 |
2.1 3.1 2.1 |
a) What is the appropriate test statistic?
---Select--- na one-way ANOVA within-subjects ANOVA two-way
ANOVA
b) Obtain/compute the appropriate values to make a
decision about H0.
Antidote: critical value = ; test
statistic =
Decision: ---Select--- Reject H0 Fail to reject H0
Dose: critical value = ; test statistic
=
Decision: ---Select--- Reject H0 Fail to reject H0
Interaction: critical value = ; test
statistic =
Decision: ---Select--- Reject H0 Fail to reject H0
c) Compute the corresponding effect size(s) and
indicate magnitude(s).
Antidote: η2
= ; ---Select--- na trivial effect small
effect medium effect large effect
Dose: η2
= ; ---Select--- na trivial effect small
effect medium effect large effect
Interaction: η2
= ; ---Select--- na trivial effect small
effect medium effect large effect
d) Make an interpretation based on the
results.
There is an antidote difference in blood concentration.
There is no antidote difference in blood concentration.
There is a dose difference in blood concentration.
There is no dose different in blood concentration.
There is an antidote by dose interaction in blood concentration.
There is no antidote by dose interaction in blood concentration.
Output using excel:
Anova: Two-Factor With Replication | ||||||
SUMMARY | Dose 5 | Dose 10 | Dose 15 | Total | ||
Antidote 1 | ||||||
Count | 3 | 3 | 3 | 9 | ||
Sum | 8.2 | 6 | 13.1 | 27.3 | ||
Average | 2.733333 | 2 | 4.366667 | 3.033333 | ||
Variance | 10.70333 | 0.21 | 2.013333 | 4.3325 | ||
Antidote 2 | ||||||
Count | 3 | 3 | 3 | 9 | ||
Sum | 3.4 | 4.5 | 7.3 | 15.2 | ||
Average | 1.133333 | 1.5 | 2.433333 | 1.688889 | ||
Variance | 0.003333 | 0.04 | 0.333333 | 0.431111 | ||
Total | ||||||
Count | 6 | 6 | 6 | |||
Sum | 11.6 | 10.5 | 20.4 | |||
Average | 1.933333 | 1.75 | 3.4 | |||
Variance | 5.050667 | 0.175 | 2.06 | |||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Sample | 8.133889 | 1 | 8.133889 | 3.668504 | 0.079582 | 9.330212 |
Columns | 9.814444 | 2 | 4.907222 | 2.21323 | 0.151993 | 6.926608 |
Interaction | 1.687778 | 2 | 0.843889 | 0.380606 | 0.69141 | 6.926608 |
Within | 26.60667 | 12 | 2.217222 | |||
Total | 46.24278 | 17 |
a) Test used: Two way Anova
b) Obtain/compute the appropriate values to make a decision about H0.
Antidote:
critical value = 6.927
test statistic = 2.213
Decision: Fail to reject H0
Dose:
critical value = 9.330
test statistic = 3.669
Decision: Fail to reject H0
Interaction:
critical value = 6.927
test statistic = 0.381
Decision: Fail to reject H0
c) Compute the corresponding effect size(s) and
indicate magnitude(s).
Antidote:
η²A = SSA /(SST - SSB - SSAxB) = 9.8144/(46.2428 - 8.1339 - 1.6878) = 0.2695 = 26.95%
Dose:
η²B = SSB /(SST - SSA - SSAxB) = 8.1339/(46.2428 - 9.8144 - 1.6878) = 0.2341 = 23.41%
Interaction:
η²AxB = SSAxB /(SST - SSA - SSB) = 1.6878/(46.2428 - 9.8144 - 8.1339) = 0.0597 = 5.97%
d) Make an interpretation based on the results.
There is no antidote difference in blood concentration.
There is no dose different in blood concentration.
There is no antidote by dose interaction in blood concentration.