Question

In: Statistics and Probability

An article reports measurements of the total power, on the log scale, of the heart rate...

An article reports measurements of the total power, on the log scale, of the heart rate variability, in the frequency range 0.003 to 0.4 Hz, for a group of 40 patients aged 25–49 years and for a group of 43 patients aged 50–75 years. The mean for the patients aged 25–49 years was 4 with a standard deviation of 0.23, and the mean for the patients aged 50–75 years was 3.4 with a standard deviation of 0.28. Let μX represent the population mean for the patients aged 25-49 years and let μY represent the population mean for the patients aged 50-75 years. Find a 95% confidence interval for the difference μX−μY. Round the answers to three decimal places.

The 95% confidence interval is ( , ).

Expert Solution

Mean and standard deviation for Age group(25-49) years:

Mean and standard deviation for Age group(50-75) years:

Confidence interval is calculated using the formula:

where, pooled variance

Critical value:

Calculation for 95% confidence interval for

So, the 95% confidence interval for difference of population mean is

orchestra answered 1 year ago

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