One of the authors came across an article (USA Today, 2008) that said that on average...

One of the authors came across an article (USA Today, 2008) that said that on average Americans have visited 16 states in the United States. In a survey of 50 students in her introductory statistics class, she found the average number of states the students had visited to be 9.48 and the standard deviation to be 7.13. The data were not strongly skewed.

1. Identify the observational unit for this study.

a. students

b. Americans

c. number of states

2. Identify the variable of interest and whether it is categorical or quantitative.

a. number of U.S. states visited, categorial

b. number of students, quantitative

c. number of students, categorial

d. number of U.S. states visited, quantitative

3. Regardless of your answer to part (c), state the null and the alternative hypotheses in symbols, to test whether the average number of states all students at the author’s school have visited is different from 16.

a. H0: mu = 16, Ha: mu ≠ 16

b. H0: mu = 16, Ha: mu > 16

c. H0: mu = 16, Ha: mu < 16

4. Using the 2SD approach to find a 95% confidence interval for the average number of states all students at the author’s school have visited. Round to two decimal places

Solutions

Expert Solution

1. The researcher is interested in finding out the average no. of states in US that are visited by Americans.

The unit that is being observed to arrive at the required conclusion is an American. The observational unit for this study is Ans: b. Americans

2. The variable of interest is number of U.S. states visited. Since the observations recorded for this variable are numeric in nature, the variable is quantitative in nature.

Ans: d. number of U.S. states visited, quantitative

3. To test whether the average number of states all students at the author’s school have visited,

The null hypothesis is always a negation statement/null of what we wish to test. Here, we wish to test that the average is different from 16.Hence, the null would be that the average is 16.

Ans: a. H0: mu = 16, Ha: mu ≠ 16

4. A 95% confidence interval for the average number of states all students at the author’s school have visited can be computed using the formula:

= (7.46,11.50)

The 95% confidence interval for the average number of states all students at the author’s school have visited is (7.46,11.50)

orchestra answered 10 months ago

Next > < Previous

Related Solutions

In a research article, the authors said that they used a chi-square test for independence for...

In a research article, the authors said that they used a chi-square test for independence for testing whether there is statistically significant correlation between two categorical variables. Each of categorical variables has two categories of outcomes. So, the contingency table for crossclassifying these two variables is a 2x2 table. They reported the chi-square statstic value for this test of independence and it is 5.21. Please mark all statements that are correct. A The correlation between the two categorical variables is...

In a USA Today survey, 20.8% of 144 respondents said that they aspire to have their...

In a USA Today survey, 20.8% of 144 respondents said that they aspire to have their boss’s job. Construct a 95% confidence interval estimate of all workers who aspire to have their boss’s job by completing the following questions. (Triola, 2014) Identify the following: = ______ (0.5 points) = ______ (0.5 points) Draw the standard normal curve graph for the 95% confidence interval (1 point). Calculate the zα/2 and include it in the graph (1 point for listing the zα/2,...

1. Based on the attached article that was written by Deirdre Shesgreen of the USA Today,...

1. Based on the attached article that was written by Deirdre Shesgreen of the USA Today, dated April 9, 2018, respond to the following questions: a) Distinguish between debt and deficit. b) Discuss the relationship between deficits and the debt, i.e., how does one effect the other. c) According to the head of the Peter G. Peterson Foundation, “the debt would hit its highest level since World War II in 10 years, crowding out private investment and reducing the government's...

1. Based on the attached article that was written by Deirdre Shesgreen of the USA Today,...

An article published in USA today stated that “in a study of colorectal surgery patients; 104...

An article published in USA today stated that “in a study of colorectal surgery patients; 104 were kept warm with blankets & 96 were kept cool. The results show that only 6 of those “warmed patients” developed wound infection vs. 18 who were kept cool. Let x = number of colorectal surgery patients who developed wound infection a) At the 0.02 level of significance, test the claim of the article’s headline: Warmer Surgical Patients Recover Better (higher recovery rate for...

An article published in USA today stated that “in a study of colorectal surgery patients; 104...

An article published in USA today stated that “in a study of colorectal surgery patients; 104 were kept warm with blankets & 96 were kept cool. The results show that only 6 of those “warmed patients” developed wound infection vs. 18 who were kept cool. Let x = number of colorectal surgery patients who developed wound infection At the 0.02 level of significance, test the claim of the article’s headline: Warmer Surgical Patients Recover Better (higher recovery rate for Warmer...

In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2,...

In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hired by the Better Business Bureau to investigate the complaints they received this year involving new car dealers. You plan to select a sample of new car dealer complaints to estimate the proportion of complaints the Better Business Bureau is able to settle. Assume the population proportion of complaints settled for new car dealers is .75, the same as...

Part A: A USA Today article claims that the proportion of people who believe global warming...

Part A: A USA Today article claims that the proportion of people who believe global warming is a serious issue is 0.6, but given the number of people you've talked to about this same issue, you believe it is less than 0.6. The hypotheses for this test are Null Hypothesis: p ≥ 0.6, Alternative Hypothesis: p < 0.6. You take a random sample and perform a hypothesis test, getting a p-value of 0.0831. What is the appropriate conclusion? Conclude at...

A recent article in USA Today reported that a job awaits 33% of new college graduates....

A recent article in USA Today reported that a job awaits 33% of new college graduates. The major reasons given were an overabundance of college graduates and a weak economy. A survey of 200 recent graduates from your school revealed that 80 students had jobs. At a 99% level of confidence, can we conclude that a larger proportion of students at your school have jobs? (a) State the null and alternate hypothesis. (b) Determine which distribution to use for the...

The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and...

The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 48 male consumers was $135.67, and the average expenditure in a sample survey of 34 female consumers was $68.64. Based on past surveys, the standard deviation for male consumers is assumed to be $35, and the standard deviation for female consumers is assumed to be $23. Develop a...

Subjects