Question

In: Math

In a USA Today article about an experimental vaccine for children the data found in the...

In a USA Today article about an experimental vaccine for children the data found in the table below was presented. Using the technique of Chi Square use a .05 significance level to test if there is an association between treatment type and outcome of flu. Does the vaccine appear to be effective? (Is there an association?)

Developed flu?

yes no

vaccine 14 656

placebo 95 137

Solutions

Expert Solution

Claim: There is an association between treatment type and outcome of flu.

The null and alternative hypothesis is

H0: There is no an association between treatment type and outcome of flu.

H1: There is an association between treatment type and outcome of flu.

Level of signfiicance = 0.05

Test statistic is

O: Observed frequency
E: Expected frequency.
E = ( Row total*Column total) / Grand total

yes no Total
Vaccine 14 656 670
placebo 95 137 232
Total 109 793 902
O E (O-E) (O-E)^2 (O-E)^2/E
14 80.96452 -66.9645 4484.247 55.38534
656 589.0355 66.96452 4484.247 7.612865
95 28.03548 66.96452 4484.247 159.949
137 203.9645 -66.9645 4484.247 21.98543
Total 244.93

Degrees of freedom = ( Number of rows - 1 ) * ( Number of column - 1) = ( 2 - 1) * (2 - 1) = 1 * 1 = 1

Critical value = 3.841

( From chi-square table)

Test statistic > critical value we reject null hypothesis.

Conclusion: There is an association between treatment type and outcome of flu.


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