A point charge q = 40 nC has a velocity 3* 106 m/s in the direction...

A point charge q = 40 nC has a velocity 3* 106 m/s in the direction av = 0.2 ax + 0.75 ay – 0.3 az. Calculate;
a) The magnitude of the force on the charge due to the field B = 3ax + - 4ay + 6az mT.
b) The magnitude of the force on the charge due to the field E = -2ax + 4ay + 5az kV/m
c) The Lorentz force due to the two fields in (i) and (ii) above.

Expert Solution

Manojponduru answered 1 year ago

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