Question

A m = 4.0 mg insect has acquired a charge of q = -5.5 nC by flying close to a developing thunderhead. The insect

Answer 1

1)

A m = 4.0 mg insect has acquired a charge of q = -5.5 nC by flying close to a developing thunderhead.

v = 3.2 m/s

d = 2.5 cm

in this problem direction of current is opposite of charge

opposite of electrons

electric field developed by insect is

E=Q/4pi*epsilon*d²

=9*10⁹*5.5*10^-9/6.25*10^-4

=7.92*10⁴

actually moving charge produces magnetic field

magneticfield

B=E/V

=2.475*10⁴tesla

direction will be anticlockwise according to right hand thumb rule

2)

general equation for force on moving charge

F=q(vxB)

=qvBsin (theta)

force on current carrying wire

F=BIL

THIS IS BALANCED BY INSECTS WEIGHT

mg=BIL

B=mg/IL

=qvmgsin (theta)/IL

THIS IS MAXIMUM WHEN THETA=90 DEGREES

3)

SUBSTITUTE GIVEN VALUES IN ABOVE EQUATION

ALONG NORTH

d=1.25cm

F=qvmg/IL

=-5.5 nC*3.2 m/s* 4.0 mg *9.8/ 500 A*1.25cm

=-110.38*10^-12N

b)

along west direction there is no force

c)

along south west

it means that we need to calculate the force in south direction

in the -ve direction

assuming distance is equally divided

so distance=1.25cm

calculation of force is same procedure as above