Question

In: Statistics and Probability

If Washington state has more cases of hep C reported in 2010, 105,800 than OR 79,800....

If Washington state has more cases of hep C reported in 2010, 105,800 than OR 79,800. Why is the reported prevalence rate higher in OR (3.05) than WA (2.30) per 100

assuming OR population at that time 2964621 and WA 5143186

Solutions

Expert Solution

Case 1: Washington DC

Prevalence Rate = (Cases of Hepatitis C/Population) X 100

                          = (105800/5143186) X 100 = 2.06 (given as 2.30)

Case 2: OR

Prevalence Rate = (Cases of Hepatitis C/Population) X 100

                          = (79800/2964621) X100 = 2.69 (given as 3.05)

Even though Washington State has more cases of Hepatitis C (105800) compared to OR (79800), the reported prevalence rate in OR in higher (3.05) than Washington (2.30).

REASON: Population of OR is 2964621 is less than Population of Washington (5143186). This makes the Cases of Hepatitis C per 100 population (which gives the prevalence rate) more for OR than Washington.


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