In: Statistics and Probability
SUMMARY OUTPUT |
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Regression Statistics |
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Multiple R |
0.195389 |
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R Square |
0.038177 |
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Adjusted R Square |
0.037333 |
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Standard Error |
13.69067 |
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Observations |
1142 |
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ANOVA |
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df |
SS |
MS |
F |
Significance F |
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Regression |
1 |
8481.255 |
8481.255 |
45.2492 |
2.74E-11 |
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Residual |
1140 |
213675.2 |
187.4344 |
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Total |
1141 |
222156.4 |
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Coefficients |
Standard Error |
t Stat |
P-value |
Lower 95% |
Upper 95% |
Lower 95.0% |
Upper 95.0% |
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Intercept |
40.19631 |
0.596741 |
67.35967 |
0 |
39.02547 |
41.36714 |
39.02547 |
41.36714 |
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X Variable 1 |
7.31E-05 |
1.09E-05 |
6.726752 |
2.74E-11 |
5.18E-05 |
9.45E-05 |
5.18E-05 |
9.45E-05 |
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What percentage of the observed variation in a person’s income is explained by the model?
b ]
From the ANOVA table given above, value of F-statistics is, 45.2492 and have P-value 2.74E-11.Therefore, at a 95% level of confidence our level of significance α = 5%
that is α =0.05
Hence, P-value =2.74*e^-11 < α =0.05
We reject H0 because there is strong evidence against H0 and conclude that, model is significantly fitted to the data .
C]
Here, standard error for x-variable (Age) is 1.09E-05 is small indicating less deviation between the observsd and fitted value. Also t-test for regressor gives test statistics value 6.726752 with p-value 2.74E-11.
Hence, P-value < 0.05, We do reject H0 because there is strong evidence against H0 and conclude that, that regression coefficient will be significantly affect on the model.
d]
Here, adjusted R2 =0.037333 , which indicates 3.7% percent of the observed variation in a person’s income is explained by the model.
e]
From the table,our regression equation is,
Person’s income= β0+ β1*Age
= 40.19631 + 7.31E-05*Age
To predict the value of a person’s income who is 45 years old, using this regression model,
Person’s income = 40.19631 + 7.31E-05*40
=40.1992