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The density of a 0.438 M solution of potassium chromate (K2CrO4) at 298 K is 1.063...

The density of a 0.438 M solution of potassium chromate (K2CrO4) at 298 K is 1.063 g/mL. a.Calculate the vapor pressure of water above the solution. The vapor pressure of pure water at this temperature is 0.0313 atm. Assume complete dissociation.

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Expert Solution


raoults law

   P0-P/P0 = i*Xsolute

P = vapor pressure of water above the solution = ?

p0 = vapor pressure of pure water at this temperature = 0.0313 atm

Molarity = w/w%*d*10 / Mwt

Mwt = molarmass of K2CrO4 = 194.2 g/mol

density = 1.063 g/ml

w/w% = 0.438*194.2/(1.063*10) = 8% by mass

means 8 g K2cro4 present in 100 g solution

no of mole of K2cro4 = w/mwt = 8/194.2 = 0.04 mol

no of mole of water in solution = (100-8)/18 = 5.11 mol

, XK2CrO4 = molefraction of K2CrO4 = 0.04/(5.11+0.04) = 0.0077

i = vanthof factor of K2CrO4 = 3


   (0.0313-p)/0.0313 = 3*0.0077

p = vapor pressure of water above the solution = 0.0306 atm


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