Question

In: Chemistry

What is the solubility ( in g/L) of lead(II) chromate, PbCrO4 in 0.13M potassium chromate, K2CrO4.

What is the solubility ( in g/L) of lead(II) chromate, PbCrO4 in 0.13M potassium chromate, K2CrO4.

Solutions

Expert Solution

      PbCrO4 --------> Pb+2 + CrO42-

                                              0.13

                                  s            s

                                  s           0.13+s

Ksp of PbCrO4 is 2.8*10-13

Ksp     = [Pb+2][CrO42-]

2.8*10-13    = s * (0.13+s)

       s           = 2.15*10-12 mole/L

   solubility of PbCrO4   = 2.15*10-12 moles/L

molar mass of PbCrO4   = 323g/mole

solubility of PbCrO4   = 2.15*10-12 moles/L * 323g/moles

                                 = 6.94*10-10 g/L

                                        


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