In: Chemistry
Silver chromate is more soluble in solutions containing some (less than 1 M) potassium nitrate, even though neither potassium nor nitrate show up in the BCE for the dissolution reaction
Ag2CrO4 (s) ↔ 2 Ag+(aq) + CrO4 2-(aq)
The solubility product constant (which is not the same as the solubility!) for silver chromate is Ksp = 1.1 x 10-12 making it a pretty insoluble substance. Your job is to figure out the molar solubility in pure water, then the molar solubility in a 0.25 M KNO3 aqueous solution and finally to express the change as a percent difference. To make it easier (and faster) please use the Debye-Hückel limiting law: log γx = -0.510 Zx2 (µ)1/2 to obtain the required activity coefficients and make a simple assumption about the ionic strength of water – rather than solving for it in an iterative process.