In: Accounting
Answer :
(1). Straight Line Method
Asset value | 500000 |
Salvage value | 20000 |
Depreciation base | 480000 |
No.of years | 10 |
Depreciation amount for each year | 480000/10 = 48000 |
Depreciation % | 48000/480000 = 10% |
Year | Depreciable Base | Depreciation % | Depreciation amount | Year end book value |
1 | 480000 | 10% | 48000 | 432000 |
2 | 480000 | 10% | 48000 | 384000 |
3 | 480000 | 10% | 48000 | 336000 |
4 | 480000 | 10% | 48000 | 288000 |
5 | 480000 | 10% | 48000 | 240000 |
6 | 480000 | 10% | 48000 | 192000 |
7 | 480000 | 10% | 48000 | 144000 |
8 | 480000 | 10% | 48000 | 96000 |
Depreciation amount in 5th year | 48000 |
Book value at end of 8th year | 96000 |
(2). Double decline method
In double declline methhod depreciation rate is twice as the straight line method and also depreciable base and depreciation amount very year to year. Salvage value not taken to account for calculating asset value. Asset is not depreciated below its salvage value.
Asset value | 500000 |
Salvage value | 20000 |
Depreciable base of first year | 500000 |
No.of years | 10 |
Depreciation % | 10%*2 = 20% |
Year | Depreciable base | Depreciation % | Depreciation amount | Year end book value |
1 | 500000 | 20% | 100000 | 400000 |
2 | 400000 | 20% | 80000 | 320000 |
3 | 320000 | 20% | 64000 | 256000 |
4 | 256000 | 20% | 40960 | 204800 |
5 | 204800 | 20% | 40960 | 163840 |
6 | 163840 | 20% | 32768 | 131072 |
7 | 131072 | 20% | 26214.4 | 104857.6 |
8 | 104857.6 | 20% | 20971.52 | 83886.08 |
Depreciation amount in 5th year | 40960 |
Book value at end of 8th year | 83886.08 |
(3). Sum of the year digit method
Under this method salvage value taken to account for calculating depreciable base. Here depreciable base same in each year. And depreciable base multiplied by a fraction that decrease each year.
Depreciation fraction = Year of useful life remaining / Sum of all years of useful life
Asset value | 500000 |
Salvage value | 20000 |
Depreciable base | 4800000 |
No of years | 10 |
Depreciation factor for 1st year = 10/55 = 0.1818
Year | Depreciable Base | Year of life remaining | Depreciation fraction | Depreciation amount | Year end book value |
1 | 4800000 | 10 | 0.1818 | 87272.7 | 392727.3 |
2 | 4800000 | 9 | 01636 | 78545.5 | 314181.2 |
3 | 4800000 | 8 | 0.1455 | 69818.2 | 244363.6 |
4 | 4800000 | 7 | 0.1273 | 61090.9 | 183272.7 |
5 | 4800000 | 6 | 0.1091 | 52363.6 | 130909.1 |
6 | 4800000 | 5 | 0.0909 | 43636.4 | 87272.7 |
7 | 4800000 | 4 | 0.0727 | 34909.1 | 52363.6 |
8 | 4800000 | 3 | 0.0545 | 26181.8 | 26181.8 |
Depreciation amount in 5th year | 52363.6 |
Book value at end of 8 th year | 26181.8 |
(4). Declining method with switch over to S.L
Year | Depreciable base | Depreciation % | Depreciation amount | Depreciation amount under S.L method | Year end book value |
1 | 500000 | 20% | 100000 | 48000 | 400000 |
2 | 400000 | 20% | 80000 | 48000 | 320000 |
3 | 320000 | 20% | 64000 | 48000 | 256000 |
4 | 256000 | 20% | 51200 | 48000 | 204800 |
5 | 204800 | 20% | 48000 | 48000 | 156800 |
6 | 156800 | 20% | 48000 | 48000 | 108800 |
7 | 108800 | 20% | 48000 | 48000 | 60800 |
8 | 60800 | 20% | 40800 | 48000 | 20000 |
Depreciation amount in 5th year | 48000 |
Depreacition amount in 8th year | 20000 |
(5). MACRS
This method is used for federal tax purpose. Here different rate for each year for different class asset. Here our scenatio our asset is belong to 7 year class asset. Here no salvage value is taken
Depreciation amount in 5th year | 5000000*8.93% = 44650* |
Book value at end of 8th year | 0 |
Check MACRS table for class 7 asset
In year 8 asset is fully depreciated under MACRS
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