In: Computer Science
1a. 569 (base 10)=_________(base 3) SHOW WORK
1b. 357 (base 9)=___________(base 3) SHOW WORK
1c. 10011100 (base 2)=__________(base 10) SHOW WORK
a) Divide 569 successively by 3 until the quotient is 0 569/3 = 189, remainder is 2 189/3 = 63, remainder is 0 63/3 = 21, remainder is 0 21/3 = 7, remainder is 0 7/3 = 2, remainder is 1 2/3 = 0, remainder is 2 Read remainders from the bottom to top as 210002 Answer: 210002 b) first convert 357 of base-9 to deicmal 357 => 3x9^2+5x9^1+7x9^0 => 3x81+5x9+7x1 => 3x81+5x9+7x1 => 243+45+7 => 295 Now, let's convert this decimal value of 295 to base-3 Divide 295 successively by 3 until the quotient is 0 295/3 = 98, remainder is 1 98/3 = 32, remainder is 2 32/3 = 10, remainder is 2 10/3 = 3, remainder is 1 3/3 = 1, remainder is 0 1/3 = 0, remainder is 1 Read remainders from the bottom to top as 101221 Answer: 101221 c) Converting 10011100 to decimal 10011100 => 1x2^7+0x2^6+0x2^5+1x2^4+1x2^3+1x2^2+0x2^1+0x2^0 => 1x128+0x64+0x32+1x16+1x8+1x4+0x2+0x1 => 128+0+0+16+8+4+0+0 => 156 Answer: 156