In: Math
initial value problem
y'=ty(4-y)/3, y(0)=y_0
determine the behavior of solution as t increases depends on the
initial value y_0
The answer says that y->-infinite when y_0<0. but i cannot
understand. please explain it
Using methode of seperable variables,
Using Partial fraction, we can write,
Equating like terms,
When t=0, y(0) = y_0
When,
Let take
THIS VALUE WILL BE ALWAYS POSITIVE.
Lets take y_0= -1
This valus will be always negative .