In: Math
initial value problem
y'=ty(4-y)/3, y(0)=y_0
determine the behavior of solution as t increases depends on the
initial value y_0
The answer says that y->-infinite when y_0<0. but i cannot
understand. please explain it


Using methode of seperable variables,



Using Partial fraction, we can write,




Equating like terms,











When t=0, y(0) = y_0











When,

Let take


THIS VALUE WILL BE ALWAYS POSITIVE.



Lets take y_0= -1


This valus will be always negative .
