Find the solution of the given initial value problem: y^(4)+2y′′′+y′′+8y′−12y=12sint+40e^−t y(0)=0, y′(0)=38/5, y′′(0)=4/5, y′′′(0)=−54/5

Find the solution of the given initial value problem:

y^(4)+2y′′′+y′′+8y′−12y=12sint+40e^−t

y(0)=0, y′(0)=38/5, y′′(0)=4/5, y′′′(0)=−54/5

Expert Solution

milcah answered 2 years ago

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